Question

A scooter was bought at Rs 42,000. It's value depreciated at the rate of 8% per annum. Find it's value after one year.​

Answer 1

Answer:

find depreciation and subtract it from cp

Step-by-step explanation:

cp of scooter is 42000

depreciation of value in 1 year is 8%

this 8% depreciation is on cp

so 8/100*42000

420*8 = 3360

now in 1 year 3360 rupees depreciated on scooter.

after 1 year the value of scooter will be 42000- 3360

which is 38640

Answer 2

Value = Rs 38640

Step-by-step explanation:

Given:

• Cost of scooter is Rs 42000.
• Value of scooter depreciated by 8% per annum.

To Find:

• What will be the value after one year ?

Solution: Here we have

• Principal = Rs 42000
• Rate = 8% per annum.
• Time = 1 year

Using formula

Amount = Principal (1 – Rate/100)ⁿ

• (–) because the value decreasing.

$\implies{\rm }$ A = 42000(1 – 8/100)¹

$\implies{\rm }$ A = 42000(100 – 8/100)

$\implies{\rm }$ A = 42000(92/100)

$\implies{\rm }$ A = 420 × 92

$\implies{\rm }$ A = 38640

Hence, the value after one year will be Rs 38640.

[ Another method ]

• C.P is Rs 42000.
• Value is decreasing by 8% per year.

∴ Value of scooter after 1 year will be

➮ 42000 – 8% of 42000

➮ 42000 – (8/100 × 42000)

➮ 42000 – (8 × 420)

➮ 42000 – 3360

➮ 38640

Hence, the value after one year will be Rs 38640.