Question

A scooter was bought at rs 42000 . its value depreciated at the rate of 8% per annum . find its value after 2 years

Answer 1

Answer:

Rs. 35,548.80

Step-by-step explanation:

depreciation value

= C.P (1-r/100)^n

= 42000 (1-8/100)^2

= 42000 (1-2/25)^2

= 42000 (25-2/25)^2

=42000 (23/25)^2

= 42000 × 23/25 ×23/25

= 35,548.8