A scooter was bought at rs 42000 its value depreciated at rate of 8% p.a find the value after 1 year
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Answered by
43
Given :-
Principal = ₹42000
Rate of depreciation = 8%
Time = 1 year
To Find :-
The depreciated value after a year
Solution :-
Total depreciation = 8% of ₹42000
= 3360
The total depreciation is ₹3,360
Value after 1 year = ₹(42000 - 3360)
= ₹ 38640
Therefore it's value after 1 year is ₹ 38,640
Answered by
21
A scooter was bought at Rupees 42,000. It's value depreciated at rate of 8% P.A. Find the value after 1 year.
- Principal = Rupees 42000.
- Depreciated's rate = 8 percent Per Annum.
- Time = 1 year.
- The Depreciated value after 1 year.
- The Depreciated value after 1 year = Rupees 38640.
- This question says that a scooter was bought at Rupees 42000. After that it's value depreciated at rate of 8% P.A. Afterwards it ask to find the value of deprecated rate after 1 year.
- Firstly, we know that percentage means 1 / 100. So, let's carry on as the value is given 8% . 8% means 8/100 then we write it as 8/100 after that we have to multiply 8/100 by 42000 . Afterwards we get a solution 3360 rupees. Now we have to subtract Principal - Total depreciation. After that we get our final result :)
Total depreciation = 8 % of Rupees 42000
Total depreciation = 8/100 × 42000 Rupees
Total depreciation = 8 × 420 Rupees
Total depreciation = 3360 Rupees
Hence, the total depreciation is Rupees 3360.
Value after a year = Rupees ( Principal - Total depreciation )
Value after a year = ( 42000 - 3360 ) Rupees.
Value after a year = 38,640 Ruppes
Hope it's helpful
Thank you :)
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