Question

A scooter was bought at Rs.42000. Its value depreciated at the rate of 8 percent per annum . Find its value after one year

Answer 1

Answer :

Cost of scooter ( C. P ) = Rs 42, 000
Depreciate Rate = 8%
Time ( T ) = 1 year

Value of scooter after a year

A = P [ 1 - R/100 ] ᵗ

A = 42000 [ 1 - 8/100 ] ¹

A = 42000 [ 100 - 8/100 ] ¹

A = 42000 [ 92/100 ] ¹

A = 42000 × 92/100

A = 420 × 92

A = Rs. 38640

Hence, Rs. 38640 is the value after one year

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Answer 2

HLO...

HERE IS YOUR ANSWER...

P=42000

R=8%

T=1 year ..

S.I= P×R×T

_________

100

= 42000×8×1

____________

100

= Rs. 3360.

VALUE AFTER 1YEAR=Rs.42000-Rs.3360

= Rs. 38640... Ans..

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