Question

A scooter was bought at Rs 84000. Its value
depreciated at the rate of 12% per annum.
Then its value after one year​

Answer 1

Given,

A scooter was bought at rupees 84000. Its value depreciated at the rate of $12$% per annum.

Formula,

$S.I=\frac{PTR}{100}$

$P=84000,R=12,T=1$

$S.I=\frac{84000\times12\times1}{100}\\S.I=840\times12\\S.I=1008$

Then after $1$ year scooter value $=84000-1008=82,992$

Therefore, the scooter value after one year is $82,992$ rupees.

Answer 2

As we know that,

Given:

A scooter was bought at$Rs 84000.$

Its value  depreciated at the rate of $12%$% per annum.

Find out:

Scooter value after one year.

Let us:

As we know scooter was bought at$Rs 84000.$

Whose value  depreciated at the rate of $12%$% per annum.

The $SI= PTR/100$

here,

$P= 84000$

$R= 12$

$T= 1$

So,

$=84000$×$12$×$1/100$

$=840$×$12$

$=1008$

Then,

$=84000-1008$

$=82,992$

Hence scooter value after one year is $82,992.$