A scooter was bought at rupees 42,000.ITS VALUE DEPRECIATED AT RATE OF 8%per annum.FIND its value after 1year
Mrtyunjay12:
42000×8÷100=3360 42000-3360=
38640
that's right
Answers
Answered by
4
decrease rate=42000×8/100=3360
after one year it's value =42000-3360=38640
after one year it's value =42000-3360=38640
Answered by
3
Original value of the scooter = 42000
After 1 year, 8% of 42000 = 3360.
So the value of the scooter after 1 years will be 42000 - 3360 = 38640.
So the value of the scooter after 1 years is Rupees 38640
After 1 year, 8% of 42000 = 3360.
So the value of the scooter after 1 years will be 42000 - 3360 = 38640.
So the value of the scooter after 1 years is Rupees 38640
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