a scooter was bought at rupees 42000 it’s value depreciated at the rate of 8% per annum find it’s value after one year
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1
A=42000(1−1008)1
=42000(0.92)
=38640
Value of the scooter after 1 year is Rs. 38,640.
Answered by
0
Rs 42,000 at Start
depreciation by 8% per annum
finding 8% of 42000
8/100×42000
= Rs 3,360
Thus,Rs 3360 will be depreciated after an year
42000-3360
=38,640
therefore it's value after an year will be Rs 38,640
hope it helps
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