Question

A scooter was bought at42,000. Its value depreciated at the rate of 8 % per annum . Find its value after one year

Answer 1

Answer:

This concept is same as compund interest. Value after one year = 42000(1 - 8/100) = 42000*92/100 = Rs 38640

Answer 2

Answer::

solution:-

Principal (P) = ₹42000

Rate of Deprecation =R =8% per annum

Time (t) = 1year

Amount = P ( 1- R ) t

1000

= ₹ 4200( 1- 8 ) t

100

= ₹ 4200 ( 1000 -8) t

100

= ₹ 4200 × 92

100

= ₹ 420 × 92 = ₹ 38,640.

:value of scooter after one year = 38.640