Question

A scooter was bought for ₹20,000 . Its value depreciated at the rate of 15% per annum. Find its value after 2 years.​

Answer 1

Answer:

38640

Step-by-step explanation:

Solution:

Here, Principal (P) = Rs. 42,000, Rate of Interest (R) = 8%, Time (n) = 1 years.

Amount (A) = P\left(1-\frac{R}{100}\right)^nP(1−

100

R

)

n

= 42000\left(1-\frac{8}{100}\right)^142000(1−

100

8

)

1

= 42000\left(1+\frac{2}{25}\right)^142000(1+

25

2

)

1

= 42000\left(\frac{27}{25}\right)^142000(

25

27

)

1

= 42000\times\frac{27}{25}42000×

25

27

= Rs. 38,640