A scooter was brought at Rs 42000 it's value depreciates at the rate of 8% par annum. Find its volume after one year
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Given that
Cost of scooter = ₹42,000
Rate of depreciation = 8 % p.a.
Time period = 1 year
Solution
Cost of scooter after 1 year
= P(1-R/100)
= 42,000(1-8/100)
= 42,000(100-8/100)
= 42,000(92/100)
= 42,000 × 23/25
= ₹38,640
Thanks
Given that
Cost of scooter = ₹42,000
Rate of depreciation = 8 % p.a.
Time period = 1 year
Solution
Cost of scooter after 1 year
= P(1-R/100)
= 42,000(1-8/100)
= 42,000(100-8/100)
= 42,000(92/100)
= 42,000 × 23/25
= ₹38,640
Thanks
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