A scooter was brought at rupees 42000 it's value
depreciated at the rate of 8% per annum
find its value after 2 years
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Answer:
: Value of scooter after one year = Rs 38,640
Step-by-step explanation:
Scooter was bought for 42000
So, P = 42000
Here, 8% P.A is depreciated
Depreciated means value is decreased.
So, we Put a Minus Sign in Rate
.. Rate = -8%
Since the rate is compounded,
we use the formula
A= P (1+r/100)n
Here P = 42000
R=- 8% P.A
n = Number of Years
n=1
Putting values in formula
A = 42,000 (1+ -8/100) 1
= 4200 (1-8/100)
= 4200 (100-8/100)
=4200 (92/100)
=420 x 92
= 38460
: : Value of scooter after one year = Rs 38,640 Rs 38,640
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