A scooter weighing 150 kg together with its rider moving at 36 km/hr is to take a turn of radius 30 m. What horizontal force on the scooter is needed to make the turn possible?
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Given conditions ⇒
Velocity = 36 km/hr = 10 m/s. Mass = 150 kg.
Radius = 30 m.
Horizontal Force needed must be equal to the centripetal force so that Scotter can take turn without sliding.
∴ Horizontal Force = mv²/r
= 150 × 100/30
= 500 N.
Hope it helps.
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