A scooter weighing 150kg together with its rider moving at 36 km/hr is to take a turn of radius 30 m. What force on the scooter towards the center is needed to make the turn possible? Who or what provides this? (Ans: 500N)
Answers
Mass of the scooter(m) = 150 kg.
Radius(r) = 30 m.
Velocity of the Scooter(v) = 36 km/hr.
= 36 × 5/18 = 10 m/s.
Using the Formula,
Force = mv²/r
⇒ Force = 150 × 10²/30
∴ F = 500 N.
Hence, the Centripetal Force of magnitude 500 N is acting on the scooter.
Hope it helps.
Thanks for the question!
It is definitely a very interesting question to solve and do some brainstorming.
**************************************************
Given, Mass of the scooter (m) with radius ( r 30cm) = 150 kg.
Velocity of the Scooter (v) = 36 km/hr = 36 × 5/18 = 10 m/s.
We know, Force = mv²/r
= 150 × 10²/30
= 500 N
Centripetal force of 500 N is exerted to make the turn possible.
**************************************************
Hope it helps and solves your query!!