Question

A scooterist follows a track on a ground that turns to his left by an angle 60°
after every 400 m. Starting from the given point, find the magnitude of
displacements of the scooterist at the third turn and eighth turn.

(A) 800 m, 400✓3 m (B) 400 m, 400✓3 m
(C) 400✓3 m, 800 m (D) 800 m, 800✓3 m

Answer 1

$\huge \bold \green{question}$

A scooterist follows a track on a ground that turns to his left by an angle 60°

after every 400 m. Starting from the given point, find the magnitude of

displacements of the scooterist at the third turn and eighth turn.

$\huge \bold \green{answer}$

$\purple{at \: 3 {}^{rd} \: turn}$

$\sf{ \implies \: \: displacement \: (oc) = om \: + \: mn \: + nc}$

$\mathsf{ \implies \: \: \: oc = 400 \: cos \: 60 + 400 + 400cos \: + cos60}$

$\mathsf{ \implies \: \: oc \: = \: 400(2cos \: 60 + 1)} \\ \\ \mathsf{ \implies \: \: (oc = 400(1 + 1))}$

$\mathsf{ \implies \: \: oc = 400 \times 2} \\ \\ \mathsf{ \boxed{{ \red \implies \: \: oc = 800m}}}$

$\purple{at \: {8}^{th} \: turn}$

$\mathsf{ \implies \: \: displacement \: (ob )\: = os + sb} \\ \\ \mathsf{ \implies \: \: ob = 400cos \: 30 \: +400 \: cos30 }$

$\mathsf{ \implies \: \: ob = 2(400 \times \frac{ \sqrt{3} }{2} )}$

$\mathsf {\boxed{ \implies \: ob = 400 \sqrt{3} m}}$

* Refer attachment for diagram

Additional information

• displacement is the shortest distance between two points.
• displacement is a vector quantity
• and a vector quantity has both magnitude and direction .

#BeBrainly

Answer 2

Explanation:

HLW MATE.....

HERE IS YOUR CORRECT ANSWER.......

PLZZ REFER TO THE ABOVE ATTACHMENT.....

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