A scooterist travels a certain distance with speed of 50kmh and returns back at the starting point with a speed of 40kmh . calculate 1.average speed, 2. average velocity of the whole journey.
Answers
Answer:
The answer will be:
1. Average speed = 400 / 9 km per hrs or 44.44 km/hrs.
2. Average velocity = 0.
Explanation:
We have given;
Speed of scooterist while travelling some distance = 50 kmh;
Speed of scooterist while returning from same distance = 40 kmh;
For average speed, we know that, the expression is given as;
= Total distance / time time; (i)
Now, let the distance be x kilometer(s) for he is travelling same distance twice .
Hence, time taken in traveling = (x / 50) hour (ii)
similarly, while returning, time taken = (x / 40) hour; (iii)
From equation (i), (ii), and (iii), it can be concluded that;
Avg. speed = (distance travelled by scooterist in travelling + distance travelled by scooterist in returning) / (time taken in travelling the distance once + time taken in returning)
Avg. speed = (x + x) / ( + );
= 2x / ();
= (200*2x) / 9x;
= 400x / 9x
= 400 / 9 km/hrs or 44.44 km/hrs
For average velocity, we know that, the expression is given as;
= Total displacement / time time; (iv)
Here, the scooterist goes to some distance and then he/she arrives to his/her initial position and this deduces that she/he hasn't travelled any distance if we count for any displacement.
Hence, displacement = 0 km (v)
Now, lets take time taken by scooterist, while going, be y and, while returning, be z. (vi)
From equation (iv), (v) and (vi), it can be concluded that;
Avg. velocity= (net displacement in this whole journey) / (total time taken)
Avg. velocity = (0) / (y+z);
= 0;
That's all.
Answer: