a scoter is acceleration from 36km/h to 18km/h in 4 second calculated the distance covered by it and negative acceleration produced during a motion
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Answered by
2
-3km/h. ...................!!!!!!!
Wat is this???
sory
Answered by
0
36×5/18= 10m/s^2
initial acceleration= 18×5/18= 5 m/s^2
distance cover in 4s
final acceleration- initial acceleration /time
10-5/4 = 5/4m
initial acceleration= 18×5/18= 5 m/s^2
distance cover in 4s
final acceleration- initial acceleration /time
10-5/4 = 5/4m
sory
i know its wrong
Similar questions
Final velocity v=72 km/h=20m/s.
Assuming uniform acceleration a=(v-u)/t=(20–10)/5=2m/s^2
For second part we take initial velocity=20m/s and final velocity =0m/s. t=20s is given.
Therefore ,retardation =(0–20)/20=-1m/s^2