Physics, asked by atharva1101, 10 days ago

A screw gauge has 100 divisions on the circular scale and linear distance travelled by the head scale is 5 mm in 10 complete rotation of circular scale. When nothing is placed between its studs, the zero of circular scale is 26 divisions above the reference line, it means zero error is –26 divisions on the circular scale. Now if the diameter of a wire is measured by keeping the wire between its studs, the main scale reading is 6 divisions and 48th division of circular scale coincides with the reference line. If the negative zero error of screw gauge is x mm and the measured diameter of the wire is y mm.The value of x is …………..​

Answers

Answered by kshitijdubey2007
1

Answer:

The distance moved by the screw of a screw gauge is 2 mm in four rotations and there are 50 divisions on its cap. When nothing is put between its jaws, 20th divisions of circular scale coincides with reference line, and zero of linear scale is hidden from circular scale when two jaws touch each other or zero circular scale is laying above the reference line. When plate is placed between the jaws, main scale reads 2 divisions and circular scale reads 20 divisions. Thickness of plate is.

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