A screw gauge has 100 parts all on circular scale and on a rotation of full circular scale the screw advances a distance of 2MM the least count of screw gauges
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the answer is 0.002 CM
bunny6511:
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Such a genius guy you are
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1 MSD = 2 MM
Number of circular division = 100
Least Count = 1 MSD/ NUMBER OF CIRCULAR DIVISION
= 2MM / 100
=0.02 MM
Hope this helps you
Number of circular division = 100
Least Count = 1 MSD/ NUMBER OF CIRCULAR DIVISION
= 2MM / 100
=0.02 MM
Hope this helps you
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