Question

A screw gauge has 200 equal divisions marked along the circumference of the disc and one full rotation of the disc
advances on the main scale by 0.05 cm. The least count of the screw gauge
a. 2.5 x 10^3 cm
b. 6.25 x 10^4 cm
c. 6.25 x 10^3 cm
d. 2.5 x 10^4 cm​

Answer 1

Answer:

a. 2.5 x 10^3 cm is your answer mate

Explanation:

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Answer 2

Answer:

Non of these option are correct and the correct answer is  2.5 × $10 ^{-4}$ cm .

Explanation:

Given , a screw gauge has  200 equal divisions marked along the circumference of the disc and one full rotation of the disc advances on the main scale by 0.05 cm .

Therefore , no. of division  (N) = 200

Pitch = 0.05cm

And Least count  = $\frac{Pitch }{No. of\ division}$

⇒ Least count = $\frac{0.05}{200}$ = $\frac{5}{200.(10)}$ = 2.5 × $10 ^{-4}$ cm

Hence , the least count of the screw gauge =  2.5 × $10 ^{-4}$ cm

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