Question

A screw gauge has a negative error of 5 divisions. While measuring the diameter of a wire, the reading on the main scale is 3 divisions, with the 9th circular scale division coinciding with the base line. If the main scale has 10 divisions to a centimetre and the circular scale has 100 divisions, calculate: (i) pitch, (ii) least count, (iii) observed diameter, and (iv) corrected diameter​

Answer 1

Answer:

Answer

As the number of divisions on main scale are 10 to a centimeter, so the smallest division on main scale will be 1mm and it will be the pitch (p) of the screw gauge. The number of circular divisions is n=100.

The least count of a screw gauge is L.C=p/n=1mm/100=0.01mm