Question

A screw guage has 50 divisions on its circular scale. The pitch of the screw guage is 0.5mm. What is its least count?

Answer 1

Answer:

0.01 mm is the Least Count.

Explanation:

Circular scale divisions = 50

Pitch = 0.5mm

Least Count of Screw Gauge = Pitch/Circular Scale Divisions

= (0.5/50) mm

= 0.01 mm

Hope this helps.