A screw guaze has 100 parts on circular scale and on rotation of a full circular scale,the screw advances a distance of 1 mm.the least count of gauze is
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Answer:
The Least Count is 0.001 mm.
Explanation:
Circular Scale divisions = 100
Pitch = 1mm
Least Count = Pitch/Circular Scale Divisions
= (1/100) mm
= 0.001 mm
Hope this helps.
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