A screw jack has a pitch of 10 mm and the lever of 0.5 metre. A force of 5 kg is applied on the lever and lifts a load of 1100 kg.what is its efficiency?
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Answer:
the product of pitch of screw jack and level are 0.005 square meters.
the efficiency is 220
the difference of the highest and lowest masses will result in it.
it is efficient enough yet.
Step-by-step explanation:
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Work done in one rotation = work done against gravity
i.e. F×2π×
2
1
=200×10×5×10
−3
F×2π=(mg)×pitch
F=
3.14
10
=3.18N
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