Question

A sea diver is at a depth of 2 km in the sea. Given density of sea water = 1.025 g/cc. The pressure on the diver is
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Answer 1

d = 1.025 g / cc

1kg = .001 g

& 1m^3 = 0.000001 cc

so d = 1.025 × 0.001 / 0.000001 = 1025 kg / m^3

so now , p = h × g × d

= 2000 × 9.8 × 1025 = 20090000 kg /m-s^2