Question

A sealed storage tank contains water to a height of 25m. The air above the water inside the tank has a gauge pressure of 4.5 atm. How fast will water flow out of a hole that is located at the bottom the tank?​

Answer 1

Answer:

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Class 11

>>Physics

>>Mechanical Properties of Fluids

>>Applications and Limitations of Bernoulli's Law

>>A sealed tank contains water to a height

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A sealed tank contains water to a height of 11 m and air at 3 atm. Water flower out from the bottom of a tank through a small hole. The velocity of efflux is (g=10ms

−2

)

Medium

Solution

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Correct option is D)

According to Bernaulis theoram

0.01×10

5

×3+ρgh=

2

1

ρv

2

3.03×10

5

+1000×10×11=

2

1

×1000v

2

v=

1000

4.13×10

5

×2

v=28.6m/s

Answer 2

Given,

height=25m

gauge pressure=4.5atm

To Find,

V=?

Solution,

According to Bernaulis's theorem

0.01×10^5×3+ρgh=1/2ρv²

3.03×10^5+1000×10×11=1/2×1000v²

v=$\sqrt{4.3*10^5*2/1000}$

v=28.6m/s

Thus the water flow out of a hole that is located at the bottom of the tank v= 28.6m/s

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