Physics, asked by isha3697, 1 year ago

A seamless pipe with 80 cm diameter carries a fluid under a pressure of 2 n/mm2. if the permissible tensile stress is 100 n/mm2, the minimum required thickness of the pipe is

Answers

Answered by madeducators3
2

Given:

A cylindrical pipe with diameter 80 cm carries a fluid under a pressure

=2\frac{N}{mm^{2} }. The permissible tensile stress is 100 \frac{N}{mm^{2} } .

To Find:

Minimum thickness of pipe required

Solution:

Thin pressure vessels

Two types of stresses are generated in a pressure vessel carrying fluid

Hoop stress and longitudinal stress

Hoop stress- stress in circumferential or radial direction

Longitudinal stress- stress along the length of pressure vessel

hoop stress = \frac{Pd}{2t}

longitudinal stress= \frac{Pd}{4t}

hoop stress> longitudinal stress

Hence failure must be protected from hoop stress.

permissible tensile stress = Hoop stress

100 = \frac{(2)(800)}{(2)(t)} \\t = 8 mm

Thickness of the pipe is 8mm.

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