Question

A searchlight takes 100 A at 80 V. It is to be operated from a 220 V supply. Find the value of the resistor to be connected in series.

Answer 1

I = 100A
V1 = 80V
V2 = 220V

R1 = V1/I
= 80/100
= 4/5

R2 = V2/I
= 220/100
= 11/5

Rs = R1 + R2
= 4/5 + 11/5
= 3ohm

Hope it helps u

Answer 2

Answer:

Data Given:

I = 100 A

V1 = 80 V

V2 = 220 V

R1 = V1/I

=80/100

=0.8

R2 = V2/I

= 220/100

=2.2

RS = R1 - R2

=0.8 - 2.2

= 1.4 Ohm