a seat of paper measures 30 cm by 20 CM 4 cm wide is cut from it around find the area of the remaining sheet and also the area of the strip cut out
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Answer:
336 sq cm
Step-by-step explanation:
Let us assume that ABCD is a rectangle with lenght 30 cm and breadth 20 cm.
So area of sheet = l×b
= 30×20= 600 sq Cm.
Now, 4cm strip of width is cut out, then we obtain a rectangle STUV with length = 30-(4+4) =22 cm.
and breadth= 20-(4+4)= 12cm.
so, area of remaining portion = 22×12=264 sq cm.
Area of the strip = area of ABCD- area of STUV
=(600-264)
=336 sq cm.
Hope it helps you.
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