Question

A secant is drawn from a point P to a circle so that it meets the circle first at A, then goes through the centre, and leaves the circle at
B. If the length of the tangent from P to the circle is 12 cm, and the radius of the circle is 5 cm, then the distance from P to A is

Answer 1

Step-by-step explanation:

Given-

O is the centre of a circle of radius=OT=OR=5cm. PT is the tangent to the circle from P at T. OP=13cm. To find out- PT=?

Solution-

∠OTP=90

o

since the tangent to a circle makes 90

o

angle with the radius at the point of contact.

∴ΔOTP is a right one with OP as the hypotenuse.

So, applying Pythagoras theorem, we have PT=

OP

2

−OT

2

=

13

2

−5

2

cm=12cm

Thus the correct answer is 12cm

Answer 2

If the length of the quadrilateral are in the ratio of the dignity