Question

A second degree polynomial passes through (0,1),(1,3),(2,7) and (3,13). Find the polynomial.

Answer 1

Answer:

i dont know ? what is this

Answer 2

Given :  A second degree polynomial passes through (0,1),(1,3),(2,7) and (3,13).

To Find :   the polynomial.

Solution:

A second degree polynomial passes through (0,1),(1,3),(2,7) and (3,13)

Let say polynomial is

y = ax² + bx + c

(0,1

=> 1  = 0 + 0 + c

=> c = 1

Hence y = ax²  + bx + 1

(1,3)

=> 3 =  a  + b + 1  

=> a + b = 2

(2,7)

=> 7  = 4a  + 2b + 1

=> 4a + 2b = 6

=> 2a + b = 3

=> a  = 1   and   b = 1

y  = x²  + x + 1

Lets verify  3 , 13

13 = 3² + 3 + 1

Hence verified

so polynomial is   x²  + x + 1

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