A second-order reaction has an initial concentration of the reactants of b.4 moles/litre (0.4 mol/am). The reaction is 30 percent complete in 80 min (4800 8). Calculate the rate constant and the time 1t would take for the reaction to be 80 percent complete.
1. 1.48 x 104 sec
2. 2.48 x 104 sec
3. 3.48 x 101 sec
4. 4.48 x 104 sec
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1
Answer:
4.48 x 104 sec
Explanation:
Given, K=6.8×10
−4
s
−1
; [A
o
]=0.04 M;
t=20 min=20×60=1200 sec
K=
t
2.303
log
[A
t
]
1
[A]
o
⟹6.8×10
−4
=
1200
2.303
log
10
(
[A
t
]
0.04
)
⟹Antiog(0.3545)=
[A
t
]
0.04
⟹2.261=
[A
t
]
0.04
⟹[A
t
]=0.0177 M
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