Question

A second order reaction in which the initial
concentration of both the reactants are same,
25% completed in 600 seconds. How long wil
take for the reaction to go to 75% completion​

Answer 1

Answer:

Answer:See the attachment

Answer:See the attachmentHope it helps you

Answer 2

Answer:



Step-by-step explanation:

The second order equation when both the reactants have same concentration

K=1/t×/xa(a-x)

If a=100,x=25,t=600seconds

So k=1/600×25/100×(100-25)

When a=100,x=75,t=

T=1/k×75/100×25

Substituting the value of k,

t=600×100×75/25×75/100×25

t=5400seconds