Question

A second pendulum is taken to the moon. If the time period on the surface of the moon is 4.90 seconds,what will be the acceleration due to gravity of the moon? Also,prove that the acceleration due to gravity of the moon to be 1/6th that of the earth?​

Answer 1

Answer:

Therefore, the time period of a second's pendulum on the surface of the moon will be $2\sqrt 6 s$.