Question

A second 's pendulum is taken to a place where acceleration due to gravity  "g" falls to one - ninth . What will be its new time period?

     2 s

     4 s

     6 s

     8 s

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Answer 1

Answer:This may help you

Explanation:

Time period of a pendulum is inversely proportional to the square root of acceleration due to gravity. given that gravity falls to one-fourth. So the time period becomes 2 times the original time period.

Answer 2

Answer:

t=2pi$\sqrt{l} \div \sqrt{g}$

T=2 $\pi$$\sqrt{l} \div \sqrt{g \div 9 }$

=3×2$\pi$$\sqrt{l \div g}$

T= 6 sec