A second's pendulum is taken to a place where acceleration due to gravity, falls to 1/9. How is the time period affected, if at all? Find the new time period, if any
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Answer:
New time period will be 9T
Explanation:
We know that,
Time period = T = 2π√(L/g) where, L is length of pendulum
g is acceleration due to gravity
Hence,
T ∝ 1/√g
If T is the initial time period
g is the initial acceleration due to gravity
T' is the new time period
g' is the new acceleration
Given that
g' = g/9
T : T' = (1/√g) : (1/√g')
T : T' = √g' : √g
T : T' = √g/9 : √g
T : T' = 1/9 : 1
T : T' = 1 : 9
T/T' = 1/9
9T = T'
Therefore the new time period will be 9 times the new time period
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