Physics, asked by armaansingh79757, 10 months ago

A second's pendulum is taken to a place where acceleration due to gravity, falls to 1/9. How is the time period affected, if at all? Find the new time period, if any ​

Answers

Answered by zahaansajid
2

Answer:

New time period will be 9T

Explanation:

We know that,

Time period = T = 2π√(L/g)    where, L is length of pendulum

                                                             g is acceleration due to gravity

Hence,

T ∝ 1/√g

If T is the initial time period

  g is the initial acceleration due to gravity

  T' is the new time period

  g' is the new acceleration

Given that

g' = g/9

T : T' = (1/√g) : (1/√g')

T : T' = √g' : √g

T : T' = √g/9 : √g

T : T' = 1/9 : 1

T : T' = 1 : 9

T/T' = 1/9

9T = T'

Therefore the new time period will be 9 times the new time period

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