Question

A seconds pendulum is taken to a place where acceleration due to gravity falls to one forth. How is the time period of the pendulum affected ,if at all ? Give reason . What will be its new time period ?

Answer 1

we know that:
time period of a pendulum is given by,
T=2π√(l/g)
if acceleration due to gravity falls to 1/4. then,
T"=2π√(4l/g)
T"=2×2π√(l/g)
T"=2T
the new time period will be increased 2 times.
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