A seconds pendulum is taken to a
planet where accelaration due to
gravity is one-fourth of the value
on the earth, then the time period
on that palnet is
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Answer:
Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.
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Step-by-step explanation:
Solution. Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.
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