Math, asked by Anjupola, 18 days ago

A seconds pendulum is taken to a
planet where accelaration due to
gravity is one-fourth of the value
on the earth, then the time period
on that palnet is​

Answers

Answered by Yashkumar0007p
0

Answer:

Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.

Step-by-step explanation:

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Answered by Natasha2569
0

Step-by-step explanation:

Solution. Time period of 'a' is inversely proportional to the square root of acceleration due to gravity. Now, if the acceleration due to gravity falls to one-fourth, the time period will be doubled.

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