Question

a seconds pendulum is taken to a planet where acceleration due to gravity is 4 times than on earth what would be the time period of the pendulum on the planet​

Answer 1

Answer:

the answer will be 0.6 time period

Answer 2

The time period of the pendulum on the planet​ is 1 second.

Explanation:

The time period of the seconds pendulum is 2 second. It is given by :

$T=2\pi \sqrt{\dfrac{l}{g}}$, g is acceleration due to gravity on earth

The acceleration due to gravity on a planet is 4 times than on the Earth, g' = 4g.

On earth's surface,

$2=2\pi \sqrt{\dfrac{l}{g}}$.....(1)

On planet,

$T=2\pi \sqrt{\dfrac{l}{g'}}\\\\T=2\pi \sqrt{\dfrac{l}{4g}} ...........(2)$

Dividing equation (1) and (2) we get :

$\dfrac{2}{T}=2\\\\T=1\ s$

So, the time period of the pendulum on the planet​ is 1 second.

Learn more,

Simple Pendulum

https://brainly.in/question/5107154