Question

A section is such that numreters is multiplied by 3 and denominator is reduced by 3 and we get 8/11. if numerator is increased by 8 and denominator is doubled the we'll get 2/5. then find the fraction ?​

Answer 1

Answer:

Solution :-

Let the fraction be x/y.

Then,

According to the question

3x/y - 3 = 18/11

and x + 8/2y = 2/5

⇒ 11x = 6y - 18 and 5x + 40 = 4y

⇒ 11x - 6y + 18 = 0 and 5x - 4y + 40 = 0

By cross-multiplication , we get

⇒ x/(- 6) × 40 - (- 4) × 18 = - y/11 × 40 - 5 × 18 = 1/11 × (- 4) - 5 × (- 6)

⇒ x/- 240 + 72 = - y/440 - 90 = 1/- 44 + 30

⇒ x/- 168 = y/- 350 = 1/- 14

⇒ x = - 168/- 14 and y = - 350/- 14

⇒ x = 12 and y = 25

Hence, the answer is 12/25

Hope this will help for you

Answer 2

Answer:

sorry I don't know this question

Explanation:

try and never give up