Question

A section of a sphere is mirrored on both sides . If the magnification of an object is 1.8 when the section is used as a concave mirror , what is the magnification of an object at the same distance in front distance in front of the convex side ? give ans with explain....​

Answer 1

Answer:

Hey mate here is your answer

Explanation:

Ans : 0.6 g

Explanation :

m = -v / magnification

m= 1.8

magnification becomes double.

1.3+1.3=2.6

m/2.6 = 1.8/2.6

= 0.6 g

Hope it helps you if so,

please mark as brainliest .....

Answer 2

Given:

A sphere mirrored on both sides has a magnification of 1.8 when used as a concave mirror.

To Find:

Magnification when is used as a convex mirror with the same object distance.

Solution:

We know that the magnification of a mirror is given by,

              $m=\frac{-v}{u}$

          ⇒ $v=-1.8u$

where $u$ is the object distance and $v$ is the image distance.

We need to find the relation between object distance and the focal length $f$.

Using the mirror's formula,

         $\frac{1}{u} +\frac{1}{v} =\frac{1}{f}$

     ⇒ $\frac{1}{u} +\frac{1}{-1.8u} =\frac{1}{f}$

     ⇒ $f=1.25u$

The same focal length will remain for the convex mirror but with the opposite sign.

         $\frac{1}{u} +\frac{1}{v} =-\frac{1}{1.25u}$

     ⇒ ${v}=0.2u$

Magnification in the convex side of the section

        $m=-\frac{v}{u}$

    ⇒ $m=0.2$

Hence, the magnification of the convex mirror is equal to 0.2.