Question

A section of sphere has a radius of curvature 0.80m.both inside and outside are polished.find focal length of inside and outside surfaces

Answer 1

Answer:

-0.4m & +0.4m

Explanation:

f = - R/2 ( concave surface)

f = + R/2 (convex surface)

inside of sphere is concave & outside is convex

hence...

inside surface = - 0.80/2 = - 0.4m

outside surface = + 0.80/2 = + 0.4m