Question

A sector containing an angle of 140 is cut off from a circle of radius 9 cm and folded into a cone

Answer 1

Step-by-step explanation:

i don't know the answer

Answer 2

The surface area of cone=$99cm^2$

Step-by-step explanation:

Central angle=140 degrees

Radius of circle=9cm

Area of sector=$\frac{\theta}{360}\times \pi r^2$

Where $\theta$=Central angle

$\pi=\frac{22}{7}$

Using the formula

Area of sector=$\frac{140}{360}\times \frac{22}{7}\times (9)^2$

Area of sector=$\frac{14}{4}\times \frac{22}{7}\times 9=11\times 9$

Area of sector=$99cm^2$

Area of cone=Area of sector=99 square cm

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https://brainly.in/question/1893575:Answered by Kvnmurty