Question

A sector is formed by opening out a cone of base radius 8 cm and height 6 cm then the radius of the sector is (in cm) 4 cm 8 cm 10 cm 6 cm

Answer 1

The radius of sector will be equal to the slant height of a right circular cone of base radius $8cm$ & a vertical height $6cm$ which is given as

$=\sqrt{8^2+6^2}$

$=10 cm$      

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\boxed{\red{\bold{Answer}}}$

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$\huge\underline{\green{\bold{Given}}}$
Radius =8cm.
Height=6cm


The radius of sector will be equal to the slant height of a right circular cone of base .

$\huge\underline{\purple{\bold{Now}}}$


$\sqrt{6 {}^{2} + 8 {}^{2} } \\ \sqrt{100} \\ 10cm$

$\huge\boxed{\red{\bold{Thanks}}}$