Question

a sector of 56°, cut out from a circle, contains 17.6cm sq. Find the radius of the circle.

Answer 1

Hi ,

Let the radius of the circle = r cm

x° = 56°

A = 17.6 sq cm

Area = x°/360 × π r²

17.6 = ( 56 / 360) × ( 22/7 ) × r²

( 176 × 360 × 7 )/ ( 10 × 56 × 22 ) = r²

36 = r²

r = √36

r = 6 cm

I hope this helps you.

:)

Answer 2

We know area of area of sector= theta/360 * pie (r)square
Given area as 17.6 cm square.
So, theta/360* pie(r)square = 17.6
Theta =56

So, 56/360*22/7 (r)square= 17.6
0.489 (r) square = 17.6
(r) square= 17.6/0.489
(r) square= 36
r = 6
Radius = 6