Question

a sector of a circle makes a 127 degree angle at its centre. If the arc of the sector has length of 36mm find the perimeter of the sectora sector of a circle makes a 127 degree angle at its centre. If the arc of the sector has length of 36mm find the perimeter of the sector

Answer 1

Answer:

so perimeter of the sector = 68.46 approximately

Step-by-step explanation:

$l = \frac{x \times 2 \times \pi \times r}{360}$

X=127°

l= 36

$36 = \frac{127 \times 2 \times \frac{22}{7} r}{360}$

$r = \frac{36 \times 360 \times 7}{127 \times 2 \times 22}$

$r = 16.23...$

perimeter of sector= l+2r

= 36+2×16.23

= 36+32.46

= 68.46 mm

so perimeter of the sector = 68.46 approximately