A sector of a circle of radius 15 cm has an angle of 120". It is rolled up so that the two
binding radil are joined together to form a cone. Find the volume of the cone
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Step-by-step explanation:
Hola there
LET WE CUT OUT THE SECTOR FROM THE CIRCLE.
LENGTH OF THE ARC= 120/360 X 2 PIE r = 1/3 X 2 PIE 15 = 10 PIE.
NOW, THE SECTOR IS ROLLED TO MAKE A CONE.
RADIUS OFTHE CIRLE= SLANT HEIGHT OF THE CONE= 15 UNITS.
LENGHT OF THE ARC= CIRCUMFERENCE OF THE BASE OF THE CONE = 10 PIE.
2 PIE r = 10 PIE.
RADIUS OF THE CONE= 5 UNITS.
HEIGHT OF THE CONE= h
h2 = 152 - 52 = 200, h= 10 * root 2.
VOLUME OF THE CONE = 1/3 PIE r2 h
(TAKE VALUE OF root 2 =1.414)
= 1/3 X 22/7 X 5 X 5 X 10*root 2
= 22 X 25 X 14.14
3 X 7
= 370.33 cm3
NICE QUESTION........
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