A sector of area 100 π sq cm is rolled up into a cone of base radius 5 cm . what is its CSA and slant height
Answers
Given : A sector of area 100 π sq cm is rolled up into a cone of base radius 5 cm .
To Find : its CSA and slant height
Solution:
A sector of area 100 π sq cm is rolled up into a cone of base radius 5 cm
cone of base radius 5 cm
=> Circumference of base = 2π (5) = 10π cm
Circumference of base of cone = arc length of sector = 10π
= (α/360)2πR = 10π
=> α = 5 * 360 /R
Area of Sector = (α/360)πR² = 100π
=> α = 36000/R²
5 * 360 /R = 36000/R²
=> R = 100/5
=> R = 20
Radius = 20 cm
which will be slant height
CSA = π ( 5) * 20
= 100π cm²
CSA = 100π cm²
Slant height = 20 cm
Direct method :
Area of sector will be CSA of cone
Hence CSA = 100π cm²
CSA = πrl
100π = π* 5 * slant height
=> slant height = 20 cm
Learn More:
बवत्तीय बेलन के आधार की त्रिज्या 5 ...
brainly.in/question/13386500
From a solid cylinder of height 24 cm and diameter 10 cm, two ...
brainly.in/question/2705273
The bottom of a right cylindrical shaped vessel made from metallic ...
brainly.in/question/8993181