Math, asked by mohammedvaseemmy, 18 hours ago

À sector of central angle 45 is cut off from a circle of sadius 12cm 4) what is the rading and slant height of the Cone make from the sector?





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Answers

Answered by shaileshmishra407
0

Answer:

Let r be the base radius of the cone.

Angle of the sector, θ=120

o

Radius of the sector, R=21cm

When the sector is folded into a right circular cone, we have circumference of the base of the cone= Length of the arc

⇒2πr=

360

o

θ

×2πR

⇒r=

360

o

θ

×R

Thus, the base radius of the cone, r=

360

o

120

o

×21=7cm

Also, the slant height of the cone,

l= Radius of the sector

Thus, l=R ⇒ l=21cm

Now, the curved surface area of the cone,

CSA=πrl

=

7

22

×21=462

Thus, the curved surface area of the cone is 462sq.cm

Step-by-step explanation:

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Answered by ffp80117
0

Step-by-step explanation:

Let r be the base radius of the cone.

Angle of the sector, θ=120

o

Radius of the sector, R=21cm

When the sector is folded into a right circular cone, we have circumference of the base of the cone= Length of the arc

⇒2πr=

360

o

θ

×2πR

⇒r=

360

o

θ

×R

Thus, the base radius of the cone, r=

360

o

120

o

×21=7cm

Also, the slant height of the cone,

l= Radius of the sector

Thus, l=R ⇒ l=21cm

Now, the curved surface area of the cone,

CSA=πrl

=

7

22

×21=462

Thus, the curved surface area of the cone is 462sq.cm

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