A sector of circle of radius 12cm has the angle 120 degree. it is rolled up so that the two bounding radii are formed together to form a cone. find the tsa of cone
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CSA of the cone = area of the sector
so, πr'L = 1/3 π ×12×12=150.72 cm^2
here L will be 12cm as the two radii is joined to form the cone
so, r'= 150.72/3.14×12 =4 cm
so, area of base = π×4×4 =50.24 cm^2
so total area of the cone = CSA +AREA of base =150.72+50.24=200.96 cm^2
thanks
so, πr'L = 1/3 π ×12×12=150.72 cm^2
here L will be 12cm as the two radii is joined to form the cone
so, r'= 150.72/3.14×12 =4 cm
so, area of base = π×4×4 =50.24 cm^2
so total area of the cone = CSA +AREA of base =150.72+50.24=200.96 cm^2
thanks
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