A sector of circle of radius 15 cm has the angle 120 degree. it is rolled up to form a cone. find the volume of cone
Answers
Answered by
97
hola there
LET WE CUT OUT THE SECTOR FROM THE CIRCLE.
LENGTH OF THE ARC= 120/360 X 2 PIE r = 1/3 X 2 PIE 15 = 10 PIE.
NOW, THE SECTOR IS ROLLED TO MAKE A CONE.
RADIUS OFTHE CIRLE= SLANT HEIGHT OF THE CONE= 15 UNITS.
LENGHT OF THE ARC= CIRCUMFERENCE OF THE BASE OF THE CONE = 10 PIE.
2 PIE r = 10 PIE.
RADIUS OF THE CONE= 5 UNITS.
HEIGHT OF THE CONE= h
h2 = 152 - 52 = 200, h= 10 * root 2.
VOLUME OF THE CONE = 1/3 PIE r2 h
(TAKE VALUE OF root 2 =1.414)
= 1/3 X 22/7 X 5 X 5 X 10*root 2
= 22 X 25 X 14.14
3 X 7
= 370.33 cm3
NICE QUESTION........
LET WE CUT OUT THE SECTOR FROM THE CIRCLE.
LENGTH OF THE ARC= 120/360 X 2 PIE r = 1/3 X 2 PIE 15 = 10 PIE.
NOW, THE SECTOR IS ROLLED TO MAKE A CONE.
RADIUS OFTHE CIRLE= SLANT HEIGHT OF THE CONE= 15 UNITS.
LENGHT OF THE ARC= CIRCUMFERENCE OF THE BASE OF THE CONE = 10 PIE.
2 PIE r = 10 PIE.
RADIUS OF THE CONE= 5 UNITS.
HEIGHT OF THE CONE= h
h2 = 152 - 52 = 200, h= 10 * root 2.
VOLUME OF THE CONE = 1/3 PIE r2 h
(TAKE VALUE OF root 2 =1.414)
= 1/3 X 22/7 X 5 X 5 X 10*root 2
= 22 X 25 X 14.14
3 X 7
= 370.33 cm3
NICE QUESTION........
Answered by
8
Attachments:
Similar questions